A filament has emissivity 0.4, surface area 0.5 × 1 0 − 4 m 2 and operating temperature 2800 K. Find the power in watts (one decimal).

P = ε σ A T 4 = 0.4 × 5.67 × 1 0 − 8 × 0.5 × 1 0 − 4 × 280 0 4 = 69.7 W.

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferMedium2 min

PhysicsMediumnumerical

A filament has emissivity 0.4, surface area $0.5 \times 1 0^{- 4}$ $m^{2}$ and operating temperature 2800 K. Find the power in watts (one decimal).

Answer:

69.70

Solution:

$P = ε σ A T^{4} = 0.4 \times 5.67 \times 1 0^{- 8} \times 0.5 \times 1 0^{- 4} \times 280 0^{4} = 69.7$ W.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

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