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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoCalorimetryMedium2 minQB

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Passage / Comprehension

As an experimenting physicist, you have taken $1 kg$ of a solid at a temperature of $- 5^{\circ} C$ and heat it at a constant rate of $10 kJ/min$ . You record the temperature at different times and plot it in the graph. The graph is shown here. Neglect heat losses.

What is the ratio of specific heat capacity of liquid to the specific heat capacity of the solid?

Options:

Answer:

Solution:

Solid: $- 5^{\circ} C$ to $1 0^{\circ} C$ in $1 min$ , which is 10 kJ.
$s_{so l i d} = \frac{10000}{1 \times 15} = \frac{2000}{3} J/kg^{\circ} C$
Liquid: $1 0^{\circ} C$ to $4 0^{\circ} C$ from $2.5 min$ to $4 min$ , which is $1.5 min$ or 15 kJ.
$s_{l i q u i d} = \frac{15000}{1 \times 30} = 500 J/kg^{\circ} C$
$\frac{s _{l i q u i d}}{s _{so l i d}} = \frac{500}{2000/3} = \frac{3}{4}$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Calorimetry

⏱ 2mℹ️ Source: QB

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