Physics - W.E.P. Question with Solution | TestHub

$\begin{array}{rl}& P=\mathrm{constant}\Rightarrow \mathrm{FV}=\text{ constant }\\ & \Rightarrow \mathrm{m}\frac{\mathrm{dV}}{\mathrm{dt}}\mathrm{V}=\text{ constant }\\ & {\int }_0^{\mathrm{V}}\mathrm{VdV}=(\mathrm{C}){\int }_0^{\mathrm{t}}\mathrm{dt}\\ & \left(\frac{{\mathrm{V}}^2}{2}\right)=\mathrm{Ct}\\ & \mathrm{V}\propto {\mathrm{t}}^{1/2}\\ & \frac{\mathrm{ds}}{\mathrm{dt}}\propto {\mathrm{t}}^{1/2}\\ & {\int }_0^{\mathrm{S}}\mathrm{ds}=\mathrm{K}{\int }_0^{\mathrm{t}}{\mathrm{t}}^{1/2}\mathrm{dt}\\ & \mathrm{S}=\mathrm{K}\times \frac{2}{3}{\mathrm{t}}^{3/2}\\ & \mathrm{S}\propto {\mathrm{t}}^{3/2}\end{array}$ $\therefore$ displacement is proportional to $(\mathrm{t}{)}^{3/2}$