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PhysicsW.E.P.Conservative force & potential energyEasy2 minPYQ_2020

PhysicsEasysingle choice

An $8 kg$ metal block of dimensions $16 cm \times 8 cm \times 6 cm$ is lying on a table with its face of largest area touching the table. If $g = 10 {ms}^{- 2}$ , then the minimum amount of work done in making it stand with its length vertical is

Options:

Answer:

Solution:

When face of the largest area is touching the table, height of centre of gravity above the table $h_{1} = \frac{6}{2} = 3 cm$

With its length vertical, height of centre of gravity would become $h_{2} = \frac{16}{2} = 8 cm$

Minimum work required W = (P.E.)₂– (P.E.)₁

= mg(h₂– h₁)

$W = \frac{8 \times 10 (8 - 3)}{100} = 4 J$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Conservative force & potential energy

⏱ 2mℹ️ Source: PYQ_2020

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