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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.MiscellaneousEasy2 minQB

PhysicsEasynumerical

Two solids $A$ and $B$ of mass $1 kg$ and $2 kg$ respectively are moving with equal linear momentum. The ratio of their kinetic energies ${(K . E .)}_{A} : {(K . E .)}_{B}$ will be $\frac{A}{1},$ so the value of $A$ will be _________.

Answer:

2.00

Solution:

Kinetic energy $K = \frac{P^{2}}{2 m}, (P_{A} = P_{B})$

$K \propto \frac{1}{m}$

$\frac{K_{A}}{K_{B}} = \frac{m_{B}}{m_{A}}$

$= \frac{2}{1}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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