If the potential energy between two molecules is given by U = A r 6 + B r 12 , then at equilibrium, separation between molecules, and the potential energy are:

U = A r 6 + B r 12 f = - d U d r For equilibrium f = 0 so r = 2 B A 1 6 Then, U = A 2 4 B

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PhysicsW.E.P.Conservative force & potential energyMedium2 minQB

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If the potential energy between two molecules is given by $U = \frac{A}{r^{6}} + \frac{B}{r^{12}},$ then at equilibrium, separation between molecules, and the potential energy are:

Options:

Answer:

Solution:

$U = \frac{A}{r^{6}} + \frac{B}{r^{12}}$

$f = - \frac{d U}{d r}$

For equilibrium

$f = 0$

so $r = {(\frac{2 B}{A})}^{\frac{1}{6}}$

Then, $U = \frac{A^{2}}{4 B}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Conservative force & potential energy

⏱ 2mℹ️ Source: QB

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