Physics - W.E.P. Question with Solution | TestHub

Power of motor initially $=P_0$ Let, rate of flow of motor $=(x)$ Since, power, $$\begin{array}{l}{P}_0=\frac{\text{ work }}{\text{ time }}=\frac{mgy}{t}=mg\left(\frac{y}{t}\right)\\ \frac{y}{t}=x=\text{ rate of flow of water }=mgx...(i)\end{array}$$ If rate of flow of water is increased by $n$ times, i.e., $(nx)$. Increased power, $$P_1=\frac{mg{y}^{\prime }}{t}=mg\left(\frac{y^{\prime }}{t}\right)=nmgx...(ii)$$ The ratio of power, $$\frac{P_1}{P_0}=\frac{nmgx}{mgx};P_1:P_0=n:1$$