A pendulum is suspended by a string of length $250 cm$ . The mass of the bob of the pendulum is $200 g$ . The bob is pulled aside until the string is at $60 °$ with vertical as shown in the figure. After releasing the bob, the maximum velocity attained by the bob will be _____ $m s^{- 1}$ . (if $g = 10 m s^{- 2}$ )

Question

TestHub · Accepted Answer

Velocity will be maximum at the bottom point when potential energy of the pendulum will be zero(considering bottom point as reference for potential energy).

$\frac{1}{2} m v^{2} = m g (l - l \cos 60 °) v = \sqrt{g l} = \sqrt{10 \times 2.5} = 5 m s^{- 1}$

Physics - W.E.P. Question with Solution | TestHub

Doubts & Discussion