Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.PowerEasy2 minPYQ_2020
PhysicsEasynumerical

A small object of mass of 100g  moves in a circular path. At a given instant velocity of the object is10i^ m/s and acceleration is(20i^+10j^) m/s2. At this instant of time, rate of change of kinetic energy (inkg m2 s-3) of the object is

Answer:
20.00
Solution:

Given, mass of objectm=100 g

=100×10-3 kg

Velocity of objectv=10i^ m/s 

Acceleration of objecta=(20i^+10j^) m/s2

We know that,

d( KE ) dt =F.v=ma.v [ K.E.= 1 2 m v 2 ]

=(100×10-3)(20i^+10j^).(10i^)

=100×10-3×200

=100×2001000=20 kg m2/s3 

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Power
2mℹ️ Source: PYQ_2020

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