The potential energy of a body is given by :
$U = 40 + 6 x^{2} - 7 xy + 8 y^{2} + 32 z$
where $U$ is in joule and $x, y, z$ in meter. Deduce the $x, y$ and z components of the force (in newton) on the body when it is in position $(- 2, 0, + 5)$ :-

Question

The potential energy of a body is given by :

$U = 40 + 6 x^{2} - 7 xy + 8 y^{2} + 32 z$

where $U$ is in joule and $x, y, z$ in meter. Deduce the $x, y$ and z components of the force (in newton) on the body when it is in position $(- 2, 0, + 5)$ :-

TestHub · Accepted Answer

Given U = 40 + 6 x 2 − 7 x y + 8 y 2 + 32 z Then F x ​ = − δ x δ u ​ = − 12 x + 7 y = + 24 N [Putting x = − 2 , y = 0 ] F y ​ = δy − δ u ​ = 7 x − 16 y = − 14 N [Putting x = − 2 , y = 0 ] F z ​ = δ z − δ u ​ = − 32 N

Physics - W.E.P. Question with Solution | TestHub

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