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PhysicsW.E.P.Vertical circular motionHard2 minPYQ_2018

PhysicsHardsingle choice

A body initially at rest and sliding along a frictionless track from a height $h$ (as shown in the figure) just completes a vertical circle of diameter $A B = D$ . The height $h$ is equal to,

NEET 2018

Options:

Answer:

Solution:

To just complete a vertical circle, speed at A should be

$v_{A} = \sqrt{5 g R}$

Using energy conservation

$m g h = \frac{1}{2} m v_{A}^{2}$

$h = \frac{1}{2} \frac{v_{A}^{2}}{g} = \frac{1}{2} \frac{5 g}{g} \frac{D}{2}$ $(R = \frac{D}{2})$

$h = \frac{5 D}{4}$

Stream:NEETSubject:PhysicsTopic:W.E.P.Subtopic:Vertical circular motion

⏱ 2mℹ️ Source: PYQ_2018

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