Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.PowerHard2 minPYQ_2022
PhysicsHardsingle choice

An electric lift with a maximum load of2000 kg(lift+passengers) is moving up with a constant speed of1.5 m s-1. The frictional force opposing the motion is3000 N. The minimum power delivered by the motor to the lift in watts is :g=10 m s-2NEET 2022 (Phase 1)

Options:

Answer:
B
Solution:

Since the speed is constant the motor has to give equal and opposite upward force.

∴   F=3000N+2000×10 =23000 N

P=FV=23000×1.5 =34500 W

Stream:NEETSubject:PhysicsTopic:W.E.P.Subtopic:Power
⏱ 2mℹ️ Source: PYQ_2022

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