A particle of mass 500 g is moving in a straight line with velocity v = b x 5 2 . The work done by the net force during its displacement from x = 0 to x = 4 m is (Take b = 0 . 25 m - 3 2 s - 1 ).

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PhysicsW.E.P.Calculation of workEasy2 minQB

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A particle of mass $500 g$ is moving in a straight line with velocity $v = b x^{\frac{5}{2}}$ . The work done by the net force during its displacement from $x = 0$ to $x = 4 m$ is (Take $b = 0.25 m^{\frac{- 3}{2}} s^{- 1}$ ).

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Answer:

Solution:

According to the work-energy theorem, work done by all forces will be is equal to the change in kinetic energy.

$W_{all} = Δ K$

$= \frac{1}{2} m b^{2} (x_{2}^{5} - x_{1}^{5})$ $= \frac{1}{2} \times 0.5 \times \frac{1}{16} \times 4^{5} = 16 J$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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