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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremMedium2 minQB

PhysicsMediumsingle choice

A bullet fired into a fixed target loses half of its velocity after penetrating $3 cm$ . How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?

Options:

Answer:

Solution:

$F .3 = \frac{1}{2} m v^{2} - \frac{1}{2} m \frac{v ^{2}}{4}$ $F (3 + x) = \frac{1}{2} m v^{2}$ $x = 1 cm$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 2mℹ️ Source: QB

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