An object moving along horizontal x -direction with kinetic energy 10 J is displaced through x = ( 3 i ^ ) m by the force F = ( − 2 i ^ + 3 j ^ ) N . The kinetic energy of the object at the end of the displacement x isNEET 2024 (Re-NEET)

Work energy theorem, W al = Δ K . E ( W al = work done by all forces ) ⇒ K f − K l = F ⋅ Δ x ⇒ K f − 10 = ( − 2 i ^ + 3 j ^ ) ⋅ ( 3 i ^ ) K f − 10 = − 6 K f = 4 J

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PhysicsW.E.P.MiscellaneousMedium2 minPYQ_2024

PhysicsMediumsingle choice

An object moving along horizontal $x$ -direction with kinetic energy 10 J is displaced through $x = (3 \hat{i}) m$ by the force $F = (- 2 \hat{i} + 3 \hat{j}) N$ . The kinetic energy of the object at the end of the displacement $x$ isNEET 2024 (Re-NEET)

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Solution:

Work energy theorem, $W_{al} = Δ K . E (W_{al} =$ work done by all forces $)$ $\Rightarrow K_{f} - K_{l} = F \cdot Δ \overline{x}$ $\Rightarrow K_{f} - 10 = (- 2 \hat{i} + 3 \hat{j}) \cdot (3 \hat{i})$ $K_{f} - 10 = - 6$ $K_{f} = 4 J$

Stream:NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2024

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