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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremEasy2 minQB

PhysicsEasysingle choice

A time dependent force $F = 6 t$ acts on a particle of mass $1 kg$ . If the particle starts from the rest, the work done by the force during the first $1 \sec$ will be:

Options:

Answer:

Solution:

$m = 1 kg$
$F = 6 t$
$∴ a = \frac{F}{m} = 6 t$
$\frac{d v}{d t} = 6 t$
$∴ \int_{0}^{v_{0}} d v = \int_{0}^{1} 6 t \cdot d t$
$∴ v_{0} = 6 \times \frac{1^{2}}{2} = 3 m s^{- 1}$
$Δ w = k_{f} - k_{i} = \frac{1}{2} \times 1 \times 9 - 0 = 4.5 J$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 2mℹ️ Source: QB

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