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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workEasy2 minQB

PhysicsEasysingle choice

A block of mass $100 kg$ slides over a distance of $10 m$ on a horizontal surface. If the co-efficient of friction between the surfaces is $0.4$ , then the work done against friction (in $J$ ) is:

Options:

Answer:

Solution:

Given $m = 100 kg$

$s = 10 m$

$μ = 0.4$

The frictional force is given by

$\begin{array}{rcl} f & = & μ m g \\ = & 0.4 \times 100 \times 10 \\ = & 400 N \end{array}$

So, the work done by the force can be calculated as follows:

$\begin{array}{rcl} W & = & f \times s \\ = & 400 \times 10 \\ = & 4000 J \end{array}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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