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PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Two spherical bodies of the same mass $M$ , are moving with velocities $v_{1}$ and $v_{2}$ respectively, along the same line. These bodies collide perfectly inelastically and head-on. The loss in kinetic energy is

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Answer:

Solution:

Loss of kinetic energy = $\frac{1}{2} \frac{m_{1} m_{2}}{m_{1} + m_{2}} {(v_{1} - v_{2})}^{2}$

$= \frac{1}{2} \times \frac{M \times M}{M + M} {(v_{1} - v_{2})}^{2}$

$= \frac{M \cdot M}{2 (2 M)} {(v_{1} - v_{2})}^{2}$

= $\frac{M}{4} (v_{1} - v_{2})^{2}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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