Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Vertical circular motionMedium3 minQB

PhysicsMediummultiple choice

A small body of mass $m$ is allowed to slide on an inclined frictionless track from rest position as shown in the figure. If block successfully completes the loop of radius 1 m:

Inclined frictionless track and circular loop of radius r

Options:(select one or more)

Answer:

A, D

Solution:

At the highest point, the limiting condition is zero normal force.

$m g = \frac{m v _{H}^{2}}{r} \Rightarrow v_{H}^{2} = g r$

Conservation of energy from the release point to the highest point gives

$m g h = m g (2 r) + \frac{1}{2} m v_{H}^{2}$

$h_{m i n} = 2 r + \frac{r}{2} = \frac{5}{2} r = 2.5 m$

From the lowest point to the highest point,

$v_{L}^{2} = v_{H}^{2} + 4 g r = 5 g r$

Thus a lowest-point speed of $5 g r$ makes the normal force zero at the top.

Correct options: A, D.

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Vertical circular motion

⏱ 3mℹ️ Source: QB

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