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PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

A particle is projected vertically upwards with a speed of16 m s-1, after some time, when it again passes through the point of projection, its speed is found to be8 m s-1. It is known that the work done by air resistance is the same during upward and downward motion. Then the maximum height attained by the particle is (Takeg=10 m s-2) :

Options:

Answer:
A
Solution:

From work-energy theorem 
For upward motion 1 2 m 1 6 2 = mgh + W  (work by air resistance)
For downward motion 1 2 m 8 2 = mgh - W 1 2 1 6 2 + 8 2 = 2 gh  

or h=8 m

Subject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous
2mℹ️ Source: PYQ_2020

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