Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workEasy2 minPYQ_2020

PhysicsEasysingle choice

A force $F$ is related to the position of a particle by the relation $F = (10 x^{2}) N$ . The work done by the force when the particle moves from $x = 2 m$ to $x = 4 m$ is

Options:

Answer:

Solution:

$W = \int_{2}^{4} Fdx = \int_{2}^{4} 10 x^{2} d x = {[\frac{10 x^{3}}{3}]}_{2}^{4}$
$= \frac{10}{3} [4^{3} - 2^{3}] = \frac{10}{3} \times 56 = \frac{560}{3} J$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...