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PhysicsW.E.P.Conservative force & potential energyEasy2 minPYQ_2020

PhysicsEasysingle choice

A uniform chain of length $L$ and mass $M$ is lying on a smooth table and one-third of its length is hanging vertically down over the edge of the table. If $g$ is the acceleration due to gravity, the work required to pull the hanging part on to the table is

Options:

Answer:

Solution:

Mass of hanging portion is $\frac{M}{3}$ $h = \frac{L}{6}$ below the table top.

Therefore, the required work done is,

$W = m g h = (\frac{M}{3}) (g) (\frac{L}{6}) = \frac{M g L}{18}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Conservative force & potential energy

⏱ 2mℹ️ Source: PYQ_2020

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