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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.PowerMedium2 minQB

PhysicsMediumsingle choice

A particle of mass $m$ is moving in a circular path of constant radius $r$ such that its centripetal acceleration $a_{c}$ is varying with time $t$ as $a_{c} = k^{2} r t^{2}$ , where $k$ is a constant. The power delivered to the particle by the force acting on it is -

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Answer:

Solution:

$a_{c} = k^{2} r t^{2}$

Or $\frac{v^{2}}{r} = k^{2} r t^{2}$ Or $v = k r t$
Therefore, tangential acceleration, $a_{t} = \frac{d v}{d t} = k r$

Therefore, tangential force, $F_{t} = m a_{t} = m k r$

Only tangential force does work.

$Power = F_{t} v = (m k r) (k r t)$ $⇒Power = m k^{2} r^{2} t$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Power

⏱ 2mℹ️ Source: QB

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