Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.PowerEasy2 minPYQ_2020

PhysicsEasysingle choice

Power supplied to a particle of mass $2 kg$ varies with time as $P = \frac{3 t^{2}}{2}$ watt, where t is in seconds. If the velocity of the particle at $t = 0$ is $v = 0$ , the velocity of the particle at $t = 2 s$ will be

Options:

Answer:

Solution:

From work energy theorem, Δ K.E. = W_net

$K_{f} - K_{i} = \int P d t$

$\frac{1}{2} {mv}^{2} - 0 = \int_{0}^{2} (\frac{3}{2} t^{2}) d t$

$\frac{1}{2} (2) v^{2} = \frac{3}{2} {[\frac{t^{3}}{3}]}_{0}^{2} = 4$

$v = 2 m s^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:W.E.P.Subtopic:Power

⏱ 2mℹ️ Source: PYQ_2020

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