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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A force $F$ is related to the position of a particle by the relation $F = (10 x^{2}) N$ . The work done by the force when the particle moves from $x = 2 m$ to $x = 4 m$ is

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Answer:

Solution:

$W = \int_{2}^{4} Fdx = \int_{2}^{4} 10 x^{2} d x = {[\frac{10 x^{3}}{3}]}_{2}^{4}$
$= \frac{10}{3} [4^{3} - 2^{3}] = \frac{10}{3} \times 56 = \frac{560}{3} J$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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