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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workHard2 minQB

PhysicsHardsingle choice

A spring of force constant $800 N / m$ has an extension of $5 cm$ . The work done is extending it from $5 cm$ to $15 cm$ is

Options:

Answer:

Solution:

$W = \int_{x_{1}}^{x_{2}} F d x = \int_{x_{1}}^{x_{2}} K x d x = K [\frac{x ^{2}}{2}]_{x_{1}}^{x_{2}} = \frac{K}{2} [x_{2}^{2} - x_{1}^{2}] = \frac{800}{2} [(0.15)^{2} - (0.05)^{2}] = 8 J$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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