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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Conservative force & potential energyMedium2 minQB

PhysicsMediumnumerical

A block of mass ' $m$ ' (as shown in figure) moving with kinetic energy $E$ compresses a spring through a distance $25 cm$ when, its speed is halved. The value of spring constant of used spring will be $n E N m^{- 1}$ for $n =$ _____.

Answer:

24.00

Solution:

Using work $-$ energy theorem
$W_{net} = ∆ K E$
$W_{net} = (K_{f} - K_{i})$
$\Rightarrow - \frac{1}{2} K x^{2} = \frac{1}{2} m {(\frac{v}{2})}^{2} - \frac{1}{2} m v^{2} \Rightarrow - \frac{1}{2} K x^{2} = \frac{E}{4} - E$
$\Rightarrow \frac{1}{2} K x^{2} = \frac{3 E}{4} \Rightarrow K = \frac{3 E}{2 x^{2}}$
$\Rightarrow K = \frac{3 E}{2 \times {(\frac{1}{4})}^{2}} = 24 E N m^{- 1}$
Thus, the value of $n = 24$ .

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Conservative force & potential energy

⏱ 2mℹ️ Source: QB

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