Physics - W.E.P. Question with Solution | TestHub

Max acceleration of $8\mathrm{kg},{\mathrm{a}}_{\text{max }}=\frac{0.4\times 2\times 10}{8}=1\mathrm{m}/{\mathrm{s}}^2$, for 10 N both the block will move together therefore change in $\Delta \mathrm{K}$.E. in fram 1 and 2 are same for force greater than 10N block 2kg slips over 8kg therefore velocity of 2 kg is more than velocity of $8\mathrm{kg}.\therefore {\mathrm{W}}_3>{\mathrm{W}}_2>{\mathrm{W}}_1$