Physics - W.E.P. Question with Solution | TestHub

$a=\frac{F}{m_1+m_2}$ By work - energy theorem $\begin{array}{rl}& \left(F-m_{1}a\right)x_1+\left(m_{2}a\right)x_2-\frac{1}{2}K{\left(x_1+x_2\right)}^2=0\\ & m_2\times \frac{F}{m_1+m_2}\left(x_1+x_2\right)=\frac{K}{2}{\left(x_1+x_2\right)}^2\\ & \left(x_1+x_2\right)=m_2\times \frac{F}{m_1+m_2}\times \frac{2}{k}\\ & =\frac{1\times 1}{1.5}\times \frac{2}{20}=\frac{1}{15}m=\frac{100}{15}\mathrm{cm}=\frac{20}{3}\mathrm{cm}\end{array}$