Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremMedium3 minQB

PhysicsMediumsingle choice

The spring is compressed by distance 'a' and the system is released. The block again comes to rest when the spring is elongated by a distance b. During this process :-

diagram

Options:

Answer:

Solution:

Spring work = loss of spring PE $= \frac{1}{2} k (a^{2} - b^{2})$ - (A), (B) wrong.

Friction dissipates this over distance a + b:

$\frac{1}{2} k (a^{2} - b^{2}) = μ m g (a + b) \Rightarrow μ = \frac{k ( a - b )}{2 m g}$ - (C).

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 3mℹ️ Source: QB

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