Physics - W.E.P. Question with Solution | TestHub

The height ( $h$ )traversed by particle while going up is $h=\frac{u^2}{2g}=\frac{25}{2\times 9.8}$ Work done by gravity force $=m\overrightarrow{\mathbf{g}}\cdot \overrightarrow{\mathbf{h}}$ $=0.1\times g\times \frac{25}{2\times 9.8}\cos 180^{\circ }$[Angle between force and displacement is $180^{\circ }$ ] $\therefore W=-0.1\times \frac{25}{2}=-1.25\mathrm{J}$