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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2006

PhysicsEasysingle choice

The potential energy of a long spring when stretched by $2 cm$ is $U$ . If the spring is stretched by $8 cm$ the potential energy stored in it is:NEET 2006

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Answer:

Solution:

Potential energy of a spring $= \frac{1}{2} \times force constant \times (extension)^{2} \Rightarrow Potential energy \propto (extension)^{2} Hence \frac{U _{1}}{V _{2}} = (\frac{x _{1}}{x _{2}})^{2} \Rightarrow \frac{V _{1}}{V _{2}} = (\frac{2}{8})^{2} \Rightarrow \frac{U _{1}}{U _{2}} - \frac{1}{16} (∵ U_{1} = V)$

Stream:NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2006

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