Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minQB
PhysicsEasynumerical

In Young's double-slit experiment, the distance between slits is d = 0.25 cm and the distance of the screen D = 120 cm from the slits. If the wavelength of light used is λ=6000 A° and I0 is the intensity of central maximum, then the minimum distance of the point from the centre, where the intensity is I02 is k×10-5 m. What is the value of k?

Answer:
7.20
Solution:

I=I02=I0cos2ϕ2

cos ϕ 2 = 1 2

ϕ 2 = π 4

ϕ=π2

2 π λ y D d = π 2

y = λ D 4 d = 6 0 0 0 × 1 0 - 10 × 1.2 4 × 0.25 × 1 0 - 2

=7 · 2 × 1 0 - 5 m

Stream:JEESubject:PhysicsTopic:Wave OpticsSubtopic:YDSE
⏱ 2mℹ️ Source: QB

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