A microwave of wavelength 2 . 0 cm falls normally on a slit of width 4 . 0 cm . The angular spread of the central maxima of the diffraction pattern obtained on a screen 1 . 5 m away from the slit, wil

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A microwave of wavelength 2 . 0 cm falls normally on a slit of width 4 . 0 cm . The angular spread of the central maxima of the diffraction pattern obtained on a screen 1 . 5 m away from the slit, will be:

TestHub · Accepted Answer

In diffraction, for first minima a sin θ = λ ⇒ sin θ = λ a = 1 2 ⇒ θ = 30 ° Therefore, angular spread of central maxima will be = 2 θ = 60 º .

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