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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2020

PhysicsEasysingle choice

In YDSE $,$ the ratio of maximum and minimum intensities of the fringe system is $4 : 1 .$ The amplitudes of the coherent sources are in the ratio of

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Answer:

Solution:

$\frac{I_{m a x}}{I_{m i n}} = \frac{4}{1} = {[\frac{\sqrt{I_{1}} + \sqrt{I_{2}}}{\sqrt{I_{1}} - \sqrt{I_{2}}}]}^{2}$

$∴ 2 = \frac{\sqrt{I_{1}} + \sqrt{I_{2}}}{\sqrt{I_{1}} - \sqrt{I_{2}}}$

$∴ \sqrt{\frac{I_{1}}{I_{2}}} = 3 = \frac{A_{1}}{A_{2}}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2020

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