Physics - Wave Optics Question with Solution | TestHub

For destructive interference (dark fringes) in Young's double slit experiment, the path difference $\Delta x$ is given by $\Delta x=(2n-1)\frac{\lambda }{2}$, where $n=1,2,3,\dots$

The phase difference $\Delta \varphi$ is related to the path difference by the formula $\Delta \varphi =\frac{2\pi }{\lambda }\Delta x$

Substituting the value of $\Delta x$, we get:

$\Delta \varphi =\frac{2\pi }{\lambda }\left[(2n-1)\frac{\lambda }{2}\right]$

$\Delta \varphi =(2n-1)\pi$

Answer: $(2n-1)\pi$