Light is incident on a polarizer with intensity I 0 . A second prism called analyzer is kept at a angle of 1 5 ∘ , from the first polarizer then the intensity of final emergent light will be

Intensity of final emergent light I = 2 I 0 cos 2 ( 1 5 ∘ ) == 4 I 0 [ 1 + cos ( 3 0 ∘ ) ] = 4 I 0 ⋅ [ 1 + 2 3 ] = 4 I 0 [ 2 + 3 ]

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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsPolarizationEasy2 minPYQ_2018

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Light is incident on a polarizer with intensity $I_{0}$ . A second prism called analyzer is kept at a angle of $1 5^{\circ}$ , from the first polarizer then the intensity of final emergent light will be

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Intensity of final emergent light $I = \frac{I _{0}}{2} cos^{2} (1 5^{\circ}) == \frac{I _{0}}{4} [1 + cos (3 0^{\circ})] = \frac{I _{0}}{4} \cdot [1 + \frac{3}{2}] = \frac{I _{0}}{4} [2 + 3]$

Stream:AIIMSSubject:PhysicsTopic:Wave OpticsSubtopic:Polarization

⏱ 2mℹ️ Source: PYQ_2018

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