In a diffraction pattern, light of wavelength 580 nm is incident normally on a slit of width ' a ' The distance between slit and the screen is 2.5 m and the distance of the second order maxi

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In a diffraction pattern, light of wavelength 580 nm is incident normally on a slit of width ' a ' The distance between slit and the screen is 2.5 m and the distance of the second order maximum from the center of the screen is 14.5 mm . The value of ' a ' is

TestHub · Accepted Answer

Distance of 2 nd order maximum from the centre of the screen x = 2 d 5 D λ ​ Here, D = 2.5 m , x = 14 mm = 14 × 1 0 − 3 m ​ λ = 580 nm = 580 × 1 0 − 9 m ∴ d = 2 x 5 D λ ​ = 2 × 14 × 1 0 − 3 m ( 5 × 2.5 × 580 × 1 0 − 9 m ) ​ = 259 μ m = 0.26 × 1 0 − 3 m ​

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