Physics - Wave Optics Question with Solution | TestHub

We know that, $$\frac{I_{\max }}{I_{\min }}=\frac{{\left(\sqrt{\frac{{\omega }_1}{{\omega }_2}+1}\right)}^2}{{\left(\sqrt{\frac{{\omega }_1}{{\omega }_2}-1}\right)}^2}$$ $I_{\max }$ and $I_{\min }$ are maximum and minimum intensity ${\omega }_1$ and ${\omega }_2$ are widths of two slits $$\therefore \frac{I_{\max }}{I_{\min }}=\frac{{\left(\sqrt{\frac{1}{25}}+1\right)}^2}{{\left(\sqrt{\frac{1}{25}}-1\right)}^2}\left(\frac{{\omega }_1}{{\omega }_2}=\frac{1}{25}\text{ given }\right)$$ On solving we get, $$\frac{I_{\max }}{I_{\min }}=\frac{\frac{36}{25}}{\frac{16}{25}}=\frac{9}{4}=9:4$$