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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2020

PhysicsEasysingle choice

For an interference pattern, the maximum and minimum intensity ratio is $64 : 1$ , then what will be the ratio of amplitudes?

Options:

Answer:

Solution:

Since, we know,

$\frac{I_{m a x}}{I_{m a x}} = {(\frac{\frac{a_{1}}{a_{2}} + 1}{\frac{a_{1}}{a_{2}} - 1})}^{2}$

Given, $\frac{I_{m a x}}{I_{m i n}} = \frac{64}{1}$

$\Rightarrow \frac{64}{1} = {(\frac{a_{1} + a_{2}}{a_{1} - a_{2}})}^{2}$

$\Rightarrow \frac{a_{1} + a_{2}}{a_{1} - a_{2}} = 8$

$\Rightarrow \frac{a_{1}}{a_{2}} = \frac{8 + 1}{8 - 1} = \frac{9}{7}$

$∴ \frac{a_{1}}{a_{2}} = \frac{9}{7}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2020

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