Physics - Wave Optics Question with Solution | TestHub

For maxima,

$\Delta \text{x}=d\; sin\theta =\text{n}\lambda$

$\therefore sin\theta =\frac{\text{n}\lambda }{\text{d}}=\frac{\text{n}\times 2000}{7000}$

Since$sin\theta$cannot be greater than$1$.

Hence,$\mathrm{n}=0, 1, 2, 3$only

$\therefore$$3$maxima on both side of screen and$1$central maxima will be obtained.

$\therefore$Total maxima$=7$