In a Young's double slit experiment the intensity at a point where the path difference is 6 λ ( λ being the wavelength of the light used) is I . If I 0 denotes the maximum intensity, I 0 I

Question

In a Young's double slit experiment the intensity at a point where the path difference is $\frac{λ}{6}$ ( $λ$ being the wavelength of the light used) is $I$ . If $I_{0}$ denotes the maximum intensity, $\frac{I}{I _{0}}$ is equal to

Options:

Answer:

D

Solution:

$\frac{I}{I _{m a x}} = cos^{2} (\frac{ϕ}{2})$

TestHub · Accepted Answer

I m a x ​ I ​ = cos 2 ( 2 ϕ ​ )

Physics - Wave Optics Question with Solution | TestHub

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