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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsDiffractionEasy2 minPYQ_2020

PhysicsEasysingle choice

Visible light of wavelength $6000 \times 10^{- 8} c m$ falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at $60^{o}$ from the central maximum. If the first minimum is produced at $θ_{1},$ then $θ_{1}$ is close to

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Answer:

Solution:

For $2^{n d}$ minima,
$d \sin θ = 2 λ$
$\sin θ = \frac{\sqrt{3}}{2}$ (given)
$\Rightarrow \frac{λ}{d} = \frac{\sqrt{3}}{4}$ ...(1)
So, for $1^{s t}$ minima
$d s i n θ = λ$
$\sin θ = \frac{λ}{d} = \frac{\sqrt{3}}{4}$
$θ = {25.65}^{o}$
$θ \approx 25^{o}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:Diffraction

⏱ 2mℹ️ Source: PYQ_2020

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