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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEMedium2 minQB

PhysicsMediuminteger

Consider a standard YDSE setup in which a bichromatic source of light is used. Find the 2nd closest (non-zero) distance (in mm) from the central bright where the intensity is maximum. (the terms have their usual meaning) (Given : $λ_{1} = 300 nm, λ_{2} = 500 nm, d = 1 mm, D = 1 m$ )

Answer:

Solution:

Common maxima: $n_{1} λ_{1} = n_{2} λ_{2} \Rightarrow 3 n_{1} = 5 n_{2}$

First: $n_{1} = 5, n_{2} = 3$ ; second: $n_{1} = 10, n_{2} = 6$

$y = \frac{n _{1} λ _{1} D}{d} = \frac{10 \times 300 \times 1 0 ^{- 9} \times 1}{1 0 ^{- 3}} = 3 \times 1 0^{- 3} m = 3 mm$

Stream:JEESubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: QB

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