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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsDiffractionEasy2 minPYQ_2020

PhysicsEasysingle choice

In Fraunhofer diffraction pattern, slit width is 0.2 mm and screen is at 2 m away from the lens. If wavelength of light used is 5000 $Å$ then the distance between the first minimum on either side of the central maximum is ( $θ$ is small and measured in radian)

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Answer:

Solution:

$a = 0.2 \times 10^{- 3 m}, D = 2 m$

$λ = 5 \times 10^{- 7} m$

$x = \frac{λ D}{a} = \frac{5 \times 10^{- 7} \times 2}{0.2 \times 10^{- 3}}$

$∴ x = \frac{5 \times 10^{- 7}}{10^{- 4}} = 5 \times 10^{- 7 + 4} m$

$∴ x = 5 \times 10^{- 3} m$

Distance between $1^{s t}$ minima on either side

$= 5 \times 10^{- 3} + 5 \times 10^{- 3}$

$= 10 \times 10^{- 3} = 10^{- 2} m$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:Diffraction

⏱ 2mℹ️ Source: PYQ_2020

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