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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

About $5 %$ of the power of a $100 W$ light bulb is converted to visible radiation. The average intensity of visible radiation at a distance of $1 m$ from the bulb:

Options:

Answer:

Solution:

Visible power = 5 W

$∴$ Average intensity of radiation at 1 m

$= \frac{p o w e r}{4 π r^{2}} = \frac{5}{4 \times π \times 1} = 0.4 W m^{- 2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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