In biprism experiment, 21 fringes are observed in a given region using light of wavelength 480 A ˚ . If light of wavelength 560 A ˚ is used, the number of fringes in the same region will be

n 1 β 1 = n 2 β 2 21 × d λ 1 D = n 2 × d λ 2 D n 2 = 21 × λ 2 λ 1 = 560 21 × 480 = 18

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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsMiscellaneousMedium2 minPYQ_2021

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In biprism experiment, 21 fringes are observed in a given region using light of wavelength $480 \overset{˚}{A}$ . If light of wavelength $560 \overset{˚}{A}$ is used, the number of fringes in the same region will be

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Solution:

$n_{1} β_{1} = n_{2} β_{2}$ $21 \times \frac{λ _{1} D}{d} = n_{2} \times \frac{λ _{2} D}{d}$ $n_{2} = 21 \times \frac{λ _{1}}{λ _{2}} = \frac{21 \times 480}{560} = 18$

Stream:MHT_CETSubject:PhysicsTopic:Wave OpticsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2021

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