An unpolarised beam of intensity I 0 is incident on a pair of nicols making an angle of 6 0 ∘ with each other. The intensity of light emerging from the pair is

According to,Malus' law, I = I 0 cos 2 θ = I 0 ( cos 6 0 ∘ ) = I 0 × ( 2 1 ) 2 = 4 I 0

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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsPolarizationMedium2 minPYQ_2016

PhysicsMediumsingle choice

An unpolarised beam of intensity $I_{0}$ is incident on a pair of nicols making an angle of $6 0^{\circ}$ with each other. The intensity of light emerging from the pair is

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Solution:

According to,Malus' law, $I = I_{0} cos^{2} θ = I_{0} (cos 6 0^{\circ}) = I_{0} \times (\frac{1}{2})^{2} = \frac{I _{0}}{4}$

Stream:VITEEESubject:PhysicsTopic:Wave OpticsSubtopic:Polarization

⏱ 2mℹ️ Source: PYQ_2016

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