In a certain double slit experimental arrangement, interference fringes of width 1 mm each are observed when light of wavelength 5000 A ˚ is used. Keeping the setup unaltered, if the source is replaced by another of wavelength 6000 A ˚ , the fringe width will be

Fringe width, β = d λ D Since D and d are unaltered, β ∝ λ . ∴ β β ′ = λ λ ′ or β ′ = β × λ λ ′ = 1 × 5000 6000 = 1.2 mm

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PhysicsWave OpticsYDSEEasy2 minPYQ_2015

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In a certain double slit experimental arrangement, interference fringes of width $1 mm$ each are observed when light of wavelength $5000 \overset{˚}{A}$ is used. Keeping the setup unaltered, if the source is replaced by another of wavelength $6000 \overset{˚}{A}$ , the fringe width will be

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Fringe width, $β = \frac{λ D}{d}$ Since $D$ and $d$ are unaltered, $β \propto λ$ . $∴ \frac{β ^{'}}{β} = \frac{λ ^{'}}{λ} or β^{'} = β \times \frac{λ ^{'}}{λ} = 1 \times \frac{6000}{5000} = 1.2 mm$

Stream:AIIMSSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2015

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