Physics - Wave Optics Question with Solution | TestHub

It is given that the amplitudes $A_1$ and $A_2$ are in the ratio $\frac{A_1}{A_2}=\frac{3}{5}$ $\therefore$ After superposition the maximum and minimum intensities will be in the ratio $$\frac{I_{\max }}{I_{\min }}=\frac{{\left(A_1+A_2\right)}^2}{{\left(A_1-A_2\right)}^2}=\frac{(3+5{)}^2}{(3-5{)}^2}=\frac{8^2}{(-2{)}^2}=\frac{64}{4}=\frac{16}{1}$$